-16t^2+24t=0.75

Solution for -16t^2+24t=0.75 equation:

-16t^2+24t=0.75

We move all terms to the left:

-16t^2+24t-(0.75)=0

We add all the numbers together, and all the variables

-16t^2+24t-0.75=0

a = -16; b = 24; c = -0.75;
Δ = b2-4ac
Δ = 242-4·(-16)·(-0.75)
Δ = 528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{528}=\sqrt{16*33}=\sqrt{16}*\sqrt{33}=4\sqrt{33}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{33}}{2*-16}=\frac{-24-4\sqrt{33}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{33}}{2*-16}=\frac{-24+4\sqrt{33}}{-32}
$